## Documents- Single 9-block
- Thirty-two 9-blocks
- Template for 3zees
- Sample Distribution
- Guide to Sample Stalagmite Model
## Netlogo Models## Discussions- Ways of Counting
- Tree Counting
- Binary Counting
- Concatenation
- Two Square Concatenation
- Other Concatenations
- Quantity Groups
- Independent Events
- Dependent Events
- Calculating Probability
- Counting Reconsidered
- Probabiliy Formula
- Independent Events Formula
- Apply Independent Events Formula
- Stalagmite Riddle
## Related Links |
## Calculating ProbabilityLet's calculate the probability of rolling two sixes. We can start by looking at all the pairs that can possibly be rolled:
There are thirty-six possibilities all together (notice that 36=6*6=6^2). Out of those, there is only one pair that is 6-6, so the odds of rolling 6-6 is 1/36. Now consider the probability of rolling a number less than three followed by a number greater than two. How many ways can we do this? For the first number, we can roll a one or a two. For each of these two choices, we can roll either a 3, 4, 5, or 6:
So there are eight ways that we can get the desired events (two ways to get a number less than three followed by four ways to get a number greater than two--2*4=8). Since we have already shown that there are 36 possible combinations, the probability of our two independent events is 8/36 = 2/9. |
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